Re: [foxboro] Natural Gas Temp & Pressure compensation

David,

The formula is:

                                      T     (14.7 PSI)
Comp. Flow (SCFM) =3D (Uncomp. Flow) * --- * ------------
                                      P      (273 K)

You need to:
        > convert your DP to Uncompensated flow =3D 100 / (235 - 0) =3D 0.43
CFM
        > convert your temp. to Kelvin =3D [(5/9)*(80 - 32)] + 273 =3D 300 K

Therefore SCFM =3D 0.43 ( 300 / 100 ) * 14.7 / 273 =3D 0.069 SCFM

Thanks,
Philip Pulas
Tesoro
Golden Eagle Refinery
Martinez, CA

-----Original Message-----
From: foxboro-bounce@xxxxxxxxxxxxx [mailto:foxboro-bounce@xxxxxxxxxxxxx]
On Behalf Of David Johnson
Sent: Thursday, February 28, 2008 11:04 AM
To: Foxboro@xxxxxxxxxxxxx
Subject: [foxboro] Natural Gas Temp & Pressure compensation

Hello all,

I was wondering if someone had the formula in their back pocket for=20
taking a DP on a natural gas line and converting it to a compensated
flow.

I have a DP orifice plate that is scaled from 0-235 " water.    This, I=20
am told corresponds to  0-2000 CFM.
I have a PT scaled from 0-130 PSI
I have a TT scaled from 0-300 deg F.

So a DP of 100" H2O at 80 Deg F and 100 PSI is ??????SCFM.

So can one of you Chemical Engineers lend a hand?

Thanks,
David




=20
=20
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