Re: [foxboro] CALC block
- From: "Jim Mowrey" <jmowrey@xxxxxxxxxxxxx>
- To: <foxboro@xxxxxxxxxxxxx>
- Date: Thu, 8 Jan 2004 00:19:33 -0500
The value would not change because the block evaluates its inputs before
starting execution and will not examine them again until the next BPC; I
believe this to be true of all blocks as well.
In a related matter, I once mistakenly set an output in the CALC block and
then set it again (to a different value with different logic) a few steps
later. Since the outputs are stored in memory, but not written out to other
blocks , until the CALC block completes its logic, I never saw the first
value output from any downstream block responses.
jim
-----Original Message-----
From: foxboro-bounce@xxxxxxxxxxxxx
[mailto:foxboro-bounce@xxxxxxxxxxxxx]On Behalf Of
IQUEIROLOO@xxxxxxxxxxxxx
Sent: Wednesday, January 07, 2004 8:47 AM
To: foxboro@xxxxxxxxxxxxx
Subject: [foxboro] CALC block
Hi list, I have a question about the CALC block. Suppose that we have a =
CALC block with this instruction in the first line:
Step 1 IN RI01
and the same instruction is repeated in the 40th line, as follows:
Step 40 IN RI01
If the value of RI01 has changed in the time between those two steps in =
the same BPC, the values that the block will read will be different?.
Suppose that the CALC block and the block where the value of the RI01 =
comes from are in the same compound.
Thanks,
Ignacio Queirolo Olivera
Repsol YPF
Tel: +54 221 429-8400 ext. 26481
Fax: +54 221 429-8400 ext. 26272
mailto:iqueiroloo@xxxxxxxxxxxxx
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