Re: [foxboro] CALC block

  • From: "Bolting, Brett C." <Brett.Bolting@xxxxxxxxxxxxxxxx>
  • To: <foxboro@xxxxxxxxxxxxx>
  • Date: Wed, 7 Jan 2004 08:18:09 -0600

Well, for my two cents...
Yes, I suppose if your upstream block and/or our process is fast enough =
there could be different values between those two reads..
You could either adjust your period and phasing on the two blocks or =
better yet I think would be to just read the value you now have=20
going to RI01 to a memory location the pull that value into your =
sequence form the memory location with a LAC Mxx command.

Brett Bolting
Process Control Specialist
Equistar Chemicals
(361) 572-2570
(361) 270-8197  beeper
--
"They that would give up essential liberty for temporary safety deserve =
neither liberty nor safety."
                                                            -- Benjamin =
Franklin

> -----Original Message-----
> From: IQUEIROLOO@xxxxxxxxxxxxx [SMTP:IQUEIROLOO@xxxxxxxxxxxxx]
> Sent: Wednesday, January 07, 2004 7:47 AM
> To:   foxboro@xxxxxxxxxxxxx
> Subject:      [foxboro] CALC block
>=20
> Hi list, I have a question about the CALC block. Suppose that we have =
a =3D
> CALC block with this instruction in the first line:
>=20
> Step 1                IN RI01
>=20
> and the same instruction is repeated in the 40th line, as follows:
>=20
> Step 40               IN RI01
>=20
> If the value of RI01 has changed in the time between those two steps =
in =3D
> the same BPC, the values that the block will read will be different?.
>=20
> Suppose that the CALC block and the block where the value of the RI01 =
=3D
> comes from are in the same compound.
>=20
> Thanks,
>=20
> Ignacio Queirolo Olivera
> Repsol YPF
> Tel: +54 221 429-8400 ext. 26481
> Fax: +54 221 429-8400 ext. 26272
> mailto:iqueiroloo@xxxxxxxxxxxxx
>=20
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