[foxboro] HLBL Array Question

Gentlemen (and Ladies)

        I have a large array size is 1440 (holds 24 hours worth of 1 min sa=
mples)

        Every minute I want to update the 1 of the sample value and throw o=
ut the oldest value.

Problem 1)

        Currently I am shuffling each value 1 at a time using this loop:
----------------------------
      x :=3D 1;
      SN01 :=3D "Preparing Array for new value ....";
      WHILE (x < 1440) DO
        ARHR[x] :=3D ARHR[x+1]; {* throw out arry position 1 and shuffle *}
        x :=3D x + 1;
      ENDWHILE;
      ARHR[1440] :=3D RI01;     {* Load newest value into array position 14=
40 *}
------------------------------


        This works however just to shuffle the values takes almost 30 secon=
ds.

        Is there a quicker way to do this ?
      Is there a way to copy array position [2] through [1440] to another a=
rray using a single command ?

Problem 2)

        During the next step of my sequence I have to find the average for =
the last 24 hours so I need to find the sum of the array then divide by 144=
0. I use the following loop to find the sum:

----------------------------
   y :=3D 1;
   SUM :=3D 0;
   WHILE ( y < 1441 ) DO
     SUM :=3D SUM + ARHR[ y ];
     y :=3D y + 1;
   ENDWHILE;
   RO01 :=3D SUM/1440; {* 24 Hour rolling average *}
----------------------------

        Again it takes about 30 seconds just to find the sum of the array.

        Is there a quicker way to find the sum of an array?


Thank You,

Peter Bruley



 
 
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