RE: Service Start Failure Question Exch55 on Win2kS
- From: "White, Piers" <pwhite@xxxxxxxxxxxxxxxxxx>
- To: "[ExchangeList]" <exchangelist@xxxxxxxxxxxxx>
- Date: Mon, 29 Jul 2002 11:52:35 -0400
Under each services properties, you have a choice to choose a specific username
and password for the service to "log on" with, or you can choose the local
system account.
If the previous admin had selected the administrator account to log on as and
not the local system account, you have to maanually go in to each service and
change the password for the admin account to your new one.
They should come up without a prob after that.
Piers White
Manager, European Support
DDI: +44 (0) 207 549 8734
Mobile: +44 (0) 7786 063655
Email: pwhite@xxxxxxxxxxxxxxxxxx
-----Original Message-----
From: Fred Orcutt [mailto:forcutt@xxxxxxxxxxxxxxxxxxxxxxxxx]
Sent: 29 July 2002 03:16
To: [ExchangeList]
Subject: [exchangelist] Service Start Failure Question Exch55 on Win2kS
http://www.MSExchange.org/
Hello all,
I inherited admin of a single domain Win2000 Server structure in a small
business. Currently it is operating as a single DC, and also runs Exchange 5.5
SP4, pulling in POP mail for the clients. I don't know if it's relevant, but
there's also another Win2k server at the location, but it is not a member of
the domain, and is in workgroup mode instead.
Anyway to get to the main question. I changed the administrator password on
the DC for security reasons. The change went through fine, but on bouncing
this server and logging on as admin with the new password the Exchange services
consistently fail to start, with the log reporting a logon failure at
initialization of Exchange Directory Services. Accordingly, all the other Exch
dependent services fail to kick in as well. There is no way to start the
services, either. To correct this I returned to the previous password for
administrator and the Exch services started as usual. I'm not sure I
understand the relationship between the admin password change and the affect on
the Exch services startup. Would appreciate an explanation!
Thanks,
Fred
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