[blind-chess] Re: Alvin, Re: Problem 21 revisited

No, I really meant fxg3, what are you seeing that I missed?

Richard
  ----- Original Message ----- 
  From: alvin blazik 
  To: blind-chess@xxxxxxxxxxxxx 
  Sent: Tuesday, May 18, 2010 3:05 PM
  Subject: [blind-chess] Alvin, Re: Problem 21 revisited


  I know you mean hxg3, I get the idea, Thanks, Alvin

  ----- Original Message ----- 
  From: R Dinger 
  To: blind-chess@xxxxxxxxxxxxx 
  Sent: Tuesday, May 18, 2010 5:57 PM
  Subject: [blind-chess] Alvin, Re: Problem 21 revisited


  Hi Alvin,

  If Black plays:
  1... Qxg3+

  White will respond:
  2. fxg3 winning the Queen.

  If Black tries the other approach:
  1... Rxg3+

  White uses the same reply:
  2. fxg3 and the White Queen can now help defend the King.

  The only move that forces the White response is:
  1... Qg2+

  There is only one reply other than just resigning the game:
  2. Kxg2 and Black follows with mate!

  Finding "forcing" moves is key to chess tactical play.  And the very best 
forcing moves only allow one response--no surprises!

  Richard

  ----- Original Message ----- 
    From: alvin blazik 
    To: blind-chess@xxxxxxxxxxxxx 
    Sent: Tuesday, May 18, 2010 11:41 AM
    Subject: [blind-chess] Problem 21 revisited


    Since that was my first move, I will follow this discussion.
    1. ... Qxg3+
    2. Kh1 Rxf2# With the discovered check from the Bishop on b7.
    It seems like a good solution.
    Alvin

    Hi Puzzlers,

    Ken asked about a possible additional solution to Problem 21 (the FEN and 
answer are reproduced at the end of this message).
    He wondered why Black could not play:
    1... Rxg3+

    as the first move instead of the posted solution.

    I think this is a good question and others may have the same or similar 
questions.  Since this is a chess discussion list, maybe we should discuss the 
question.

    Would anyone like to comment on an answer to Ken's question.  I have my own 
answer, but I will wait a bit to give mine.

    Problem 21:
    7k/
    1bpp2p1/
    3bp3/
    p4B2/
    2P5/
    P3BrPq/
    1PQ2P1P/
    4RRK1

    Points 4
    Black ates in two.
    Solution:
    1... Qg2+
    2. Kxg2 Rxg3#

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