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[SI-LIST] Re: Loss tangent and Dielectric conductance
- From: "Ozgur Misman" <omism@xxxxxxxxx>
- To: si-list@xxxxxxxxxxxxx
- Date: Thu, 1 Nov 2001 09:38:16 -0700
Actually formula do exist,
I must have missed the capacitance in tmy previous E-mail
let me rewrite it as
Gd=2*pi*f *tand*C (capacitance)
C=Er*Co
Co= Eo A/d
Mick is right in saying that the dielectric loss is a property of the
material and conductance depends on the circuit as well. That link is in
the capacitance term.
The formula is derived assuming a resistance in parallel with
capaciatance.and conductance is defined as 1/resistance.
Hope this clarifies
Ozgur Misman
---------------------- Forwarded by Ozgur Misman/CHAZ/AAWW on 11/01/2001
09:34 AM ---------------------------
11/01/2001 08:51 AM
Ozgur Misman - Chandler - 5080
Sr Engineer
01 We've Just Begun
To: plaflamm@xxxxxxxx
cc: si-list@xxxxxxxxxxxxx
Subject: Re: [SI-LIST] Loss tangent and Dielectric conductance (Document
link: Ozgur Misman)
Hi Peter,
I think the for mula is : Gd (conductance)=2*pi*frequency*tand(loss
tangent)* Eo (permittivity of the free space;8.854e-12f/m)* dielectric
constant;Er
Ozgur Misman
Amkor Technology
Peter LaFlamme <plaflamm@xxxxxxxx>@freelists.org on 11/01/2001 06:45:13 AM
Please respond to plaflamm@xxxxxxxx
Sent by: si-list-bounce@xxxxxxxxxxxxx
To: si-list <si-list@xxxxxxxxxxxxx>
cc:
Subject: [SI-LIST] Loss tangent and Dielectric conductance
Hi SI Folks,
I would like to know the relationship between Loss Tangent and Dielectric
loss. In other words, If I know the "loss tangent" at a given frequency for
a particular dielectric what is the formula to convert this into the
Dielectric conductance(Gd) ?
Thanks,
Peter
--
Peter LaFlamme
Applied Micro Circuits Corp.
Staff System Applications Engineer
200 Minuteman Rd, 3rd Floor
Andover, MA 01810
978-247-8470 phone
978-623-0055 Fax
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