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[SI-LIST] Re: GND is perfect conductor?
- From: "D G" <dgun@xxxxxxxxxx>
- To: si-list@xxxxxxxxxxxxx
- Date: Fri, 05 Sep 2003 07:48:23 +0800
Jeff,
Assuming you are using ADS Momentum, you can just create/modify the substrate
from the Momentum pull-down menu. From there you can assign conductivity and
thickness properties to the ground layer or any signal layer. It should
calculate loss appropriately.
--
Daniel
----- Original Message -----
From: "Loyer, Jeff" <jeff.loyer@xxxxxxxxx>
> We routinely assume perfect conductors for ground in our field solvers.
> In fact, I don't believe you have an option of doing otherwise for ADS
> (I've got a request in for information on this, but can't get a reply
> until next week). And, for XFX, I don't know whether it comprehends any
> skin effects of the Ground plane (it says it applies the default rho
> for resistivity, but I don't know what that does for an infinitely wide
> conductor). Ansoft Q2D, on the other hand, allows setting the
> characteristics of the ground plane (since it's just another conductor).
>
> I would expect that, at current (>5GHz) frequencies, the ground plane
> losses would have a significant effect (the current in the ground plane
> would be a mirror image of that in the signal conductor), including skin
> effects. The Hall, Hall, McCall book even gives a formula for the
> effect (page 80). But, our simulators don't seem to take it into
> account.
>
> 1) Does anyone have any information (data would be preferred, vs.
> conjecture) on the effects of using a perfect vs. imperfect conductor
> for ground?
>
> 2) If ground plane losses don't have any effect, why don't they?
>
> 3) If ground plane losses do have an effect, how do you properly model
> them in XFX and/or ADS?
>
> Jeff Loyer=20
--
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