Re: Column order in indices (oracle 9.2) - solved (kind of)
From: genegurevich@xxxxxxxxxxxxxxxxxxxxx
To: oracle-l <oracle-l@xxxxxxxxxxxxx>
Date: Wed, 2 Aug 2006 08:10:34 -0500
According to Oracle the issue is a known bug 4901231 which is fixed in
oracle 9208 and oracle 10
I am currently upgrading this database to Oracle 10 and should be able to
confirm whether this is
the case.
Again, thanks to all who replied
thank you
Gene Gurevich
Oracle Engineering
224-405-4079
Wolfgang
Breitling
<breitliw@centrex To
cc.com> genegurevich@xxxxxxxxxxxxxxxxxxxxx
cc
08/01/2006 09:57 oracle-l <oracle-l@xxxxxxxxxxxxx>
AM Subject
Re: Column order in indices (oracle
9.2)
Is the partitioning based on the first(leading) column of the index? In my
experience - don't know if it's a fixed rule - a local partitioned index is
not
being used unless the partitioning column is among the predicates.
Having said that, I haven't had a chance to possibly revise that experience
with
Oracle 9.2 or 10.
Quoting genegurevich@xxxxxxxxxxxxxxxxxxxxx:
> Yechiel:
>
> The answers are yes and yes - the index is partitioned locally and I do
> have the histograms
>
> thank you
--
regards
Wolfgang Breitling
Oracle 7,8,8i,9i OCP DBA
Centrex Consulting Corporation
www.centrexcc.com
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