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RE: how to generate the output w/o using temp table

  • From: "Poras, Henry R." <Henry_Poras@xxxxxxxxxxxxxxxx>
  • To: "'oracle-l@xxxxxxxxxxxxx'" <oracle-l@xxxxxxxxxxxxx>
  • Date: Mon, 2 Aug 2004 14:43:51 -0400
Lex,

How does this compare to the Richard Snodgrass book 'Developing Time-Oriented
Database Applications in SQL'
(http://www.cs.arizona.edu/people/rts/tdbbook.pdf)?

Henry


-----Original Message-----
From: oracle-l-bounce@xxxxxxxxxxxxx
[mailto:oracle-l-bounce@xxxxxxxxxxxxx]On Behalf Of Lex de Haan
Sent: Monday, August 02, 2004 1:29 PM
To: oracle-l@xxxxxxxxxxxxx
Subject: RE: how to generate the output w/o using temp table


as an aside, if you are interested in some theory behind
this type of problems, the following book is a must:
Chris date, Hugh Darwen, and Nikos Lorentzos:
"Temporal Data and the Relational Model"
Morgan Kaufmann Publishers, ISBN 1-55860-855-9.

they introduce the concept of "packing" and "unpacking" data
over the time dimension -- which is the generalization of the issue here.

Kind regards,
Lex.

---------------------------------------------
visit my website at http://www.naturaljoin.nl
---------------------------------------------

From: oracle-l-bounce@xxxxxxxxxxxxx
[mailto:oracle-l-bounce@xxxxxxxxxxxxx]On Behalf Of Daniel Fink
Sent: Monday, August 02, 2004 18:01
To: oracle-l@xxxxxxxxxxxxx
Subject: Re: how to generate the output w/o using temp table

Somehow, you need to iterate through a list of months between the start and
end dates and find all records that fall within that
range. If you have a calendar type table, you can use that. If not, you have
to get creative. I've included some code below (part
stolen from other posters, part from my own twisted mind). *IF* the number
of months requested is greater that the number of rows in
  the vacation table, it will *not* work. A better solution would be to code
it in PL/SQL or another language.

Regards,
Daniel Fink


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